New Pattern Inequalities Questions in Quantitative Aptitude for SBI Clerk/PO 2018
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Q1.Quantity I: The age of teacher, if the average age of 36 students is 14. When teacher’s age is included the average increases by 1.
Quantity II: The age of teacher, if the average age of 19 students is 35. When teacher’s age is included the average increases by 0.5.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q2.Quantity I: Profit Percentage , if Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6.
Quantity II: Profit Percentage, if 100 toys are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q3.Quantity I: On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Quantity II: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. The selling price is:
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q4.Quantity I: A and B together can do a piece of work in 4 days. If A alone can do the same work in 6 days, then B alone can do the same work in?
Quantity II: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q5.Quantity I: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed of the tour is:
Quantity II: A went from P to Q with the speed of 60km/hr. and return back with the speed of 90km/hr. Find the average speed.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
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Solutions:-
1.Option A
Solution:
I A=a +or – nd
14+ (37*1) =14+37=51yrs.
II 35 + (20*0.5) =35+ 10=45yrs.
2.Option A
Solution:
I If the no of article bought is LCM of 6 and 5 is 30
CP of 30 articles =5/6*30=Rs25
SP of 30 articles =6/5*30=Rs36
Profit 36-25=11
Profit %ge =11/25 *100=44%
II CP of 1 toy =350/100=3.50
SP of 1toy = 48/12 =4.
Profit=4-3.5=0.5.
Profit %ge (0.5/3.5) *100=14 2/7%
3.Option C
Solution:
I. C.P. of 12 balls = S.P. of 17 balls = Rs.720.
CP of 1 ball = 720/12=Rs60.
II. SP =85% of 1400
=85/100*1400
=Rs1190.
4.Option A
Solution:
I. B work= 1/4 – 1/6 = 2/24 ==> 12 days
II. A’s 1hr work 1/4 .
(B+C’s) 1 hr work 1/3.
(A+C’s) 1hr work 1/2.
A+B+C 1hr work = 1/4+1/3=7/12.
B’s work =7/12 – 1/2=1/12
12hours.
5.Option C
Solution:
I. Total time taken = (160/64 + 160/80) =9/2hrs
Then avg speed =320/(9/2)
=320*2/9= 71.11km/hr.
II. (2*60*90)/150=72km/hr.
BEST OF LUCK !!!!!!
SAHIL
Gear up your Preparation with Doubt Classes
Q1.Quantity I: The age of teacher, if the average age of 36 students is 14. When teacher’s age is included the average increases by 1.
Quantity II: The age of teacher, if the average age of 19 students is 35. When teacher’s age is included the average increases by 0.5.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q2.Quantity I: Profit Percentage , if Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6.
Quantity II: Profit Percentage, if 100 toys are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q3.Quantity I: On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Quantity II: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. The selling price is:
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q4.Quantity I: A and B together can do a piece of work in 4 days. If A alone can do the same work in 6 days, then B alone can do the same work in?
Quantity II: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Q5.Quantity I: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed of the tour is:
Quantity II: A went from P to Q with the speed of 60km/hr. and return back with the speed of 90km/hr. Find the average speed.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
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Solutions:-
1.Option A
Solution:
I A=a +or – nd
14+ (37*1) =14+37=51yrs.
II 35 + (20*0.5) =35+ 10=45yrs.
2.Option A
Solution:
I If the no of article bought is LCM of 6 and 5 is 30
CP of 30 articles =5/6*30=Rs25
SP of 30 articles =6/5*30=Rs36
Profit 36-25=11
Profit %ge =11/25 *100=44%
II CP of 1 toy =350/100=3.50
SP of 1toy = 48/12 =4.
Profit=4-3.5=0.5.
Profit %ge (0.5/3.5) *100=14 2/7%
3.Option C
Solution:
I. C.P. of 12 balls = S.P. of 17 balls = Rs.720.
CP of 1 ball = 720/12=Rs60.
II. SP =85% of 1400
=85/100*1400
=Rs1190.
4.Option A
Solution:
I. B work= 1/4 – 1/6 = 2/24 ==> 12 days
II. A’s 1hr work 1/4 .
(B+C’s) 1 hr work 1/3.
(A+C’s) 1hr work 1/2.
A+B+C 1hr work = 1/4+1/3=7/12.
B’s work =7/12 – 1/2=1/12
12hours.
5.Option C
Solution:
I. Total time taken = (160/64 + 160/80) =9/2hrs
Then avg speed =320/(9/2)
=320*2/9= 71.11km/hr.
II. (2*60*90)/150=72km/hr.
BEST OF LUCK !!!!!!
SAHIL
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