Memory Based Inequalities Questions in Quantitative Aptitude SBI PO 2018

Memory Based Inequalities Questions in Quantitative Aptitude SBI PO 2018(with Detailed Solution)

Q1.Quantity I: Distance, if a man covers a distance of 22 hours. he covers first half at 15 km/hr and 2nd half at 18 km/hr
Quantity II: Distance, if a man covers a distance in three equal parts in 20 hours. He covers first part at 10 km/hr, 2nd at 15 km/hr and 3rd at 30 km/hr
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Answer
  Option A
Solution:
Quantity I:
(2*15*18)/33 * 22 = 360 km
Quantity II:
Average speed will become 15 km/hr
So distance 15*20 = 300 km
I>II
Q2.Quantity I: Cost price, if a man reduces the selling price by Rs 12 and by this the profit of 5% converts to a loss of 2.5%
Quantity II: Cost Price, if a man increases the selling price by Rs 42 and by this the loss of 20% converts to a profit of 10%
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Answer
  Option A
Solution:
I:                                                 CP           SP
Gain= 5% = 1/20                      20          (20+1) = 21 ………..(1)
Loss = 2.5% = 1/40                  40           (40-1)=39 …..……..(2)
Multiply (1) by 2 to make CP same in both
So from (1) CP = 40, SP = 42
Now difference in SP = 42-39 = 3
So 3== 12
1 == 4
So 40 == 160
II: Similarly do II part
.                                                 CP           SP
Loss= 20% = 1/5                     5              4   ………..(1)
Gain = 10% = 1/10                  10           11 …..……..(2)
Multiply (1) by 2 to make CP same in both
So from (1) CP = 10, SP = 8
Now difference in SP = 11-8 = 3
So 3== 42
1 == 14
So 10 == 140
So I > II

Q3.Quantity I: Age of father, if age of Abhishek is 1/6th of his father’s and 10 years after Abhinav’s age becomes half of Abhishek’s father’s age.
Quantity II: Age of father, if 5 years ago age of A’s father was three times the age of A and 5 years hence his age will be double A’s age.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Answer
  Option C
Solution:
I:
………………………Abhishek……………Father
………………………..…..1…………………….6                             (1)
10 years after.    Abhinav              Father
.                                 1 ……………………2                              (2)
Now Abhivav is 10 years old so after 10 years he will be 20
Put in (1)
father = 40
Now 40-10 = 30
II:
.                             A              A’s father
5 years ago          1                       3
5 years hence      1                      2
So 3-2 = 1
1 == 10
3 == 30
So 30+5 = 35
II>I

Q4.Quantity I: Find amount after 4 years, if rate of interest is 20% and the principal amount is Rs 8000
Quantity II: Find the amount after 4 years, if Rs 10,000 becomes Rs 12,000 in 2 years at compound interest.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established
Answer
  Option E
Solution:
I:  SI = 20*4 = 80%
100% = 8000
180% = Rs 14400
II.
10000 : 12000 :: 12000 : x
x = 12000*12000/10000 = Rs 14400
II>I

Q5.Quantity I: Share of A, if A and B invested Rs 22000 and Rs 25000 respectively in a scheme. After half a year A reduces his investment by 50% and B reduces by 20% and they earn a profit of Rs 5200 after a year.
Quantity II: Share of A, if A and B invested Rs 30000 and Rs 35000 in a scheme. Both increase their investments by Rs 5000 after 8 months and they earn a profit of Rs 6150 after a year.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥  Quantity I
E) Quantity I = Quantity II or Relation cannot be established

Answer
  Option C
Solution:
I:
22000        :        25000
*6                          *6
=132                      =150
11000        :        20000
*6                          *6
=66                      =120
132+66      :     150+20
11 : 15
A’s share = 11/26 * 5200 = Rs 2200
II:
30000        :        35000
*8                          *8
=240                      =280
35000        :        40000
*4                          *4
=140                      =160
240+140      :     280+160
19 : 22
A’s share = 19/41 * 6150 = Rs 2850
So II > I

Best Wishes!!!!!
Sahil Malhotra

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